Hi Community! been a few weeks and now I am back with a tricky question.
I have grouped data and now I have a data set similar to this:
Pricing Cost Volume Value Name Change
1 0 0 0 ABC -0.2
1 0 0 0 DBC -0.1
1 0 0 0 XYZ +0.7
1 1 0 0 ABC -0.4
1 1 0 0 DBC -0.7
1 1 0 0 XYZ +0.9
1 0 3 0 ABC -0.1
1 0 3 0 DBC -0.6
1 0 3 0 XYZ +0.5
My goal is to review the change differences for each "name" column that has the same pricing, cost, volume and value.
How could I do approach this?
Thank you so much!
Natalia.
Solved! Go to Solution.
Hi @nataliad18
It maybe be something like this. Can you provide some sample input and expected output it will help us get a better understanding of the usecase.
Hope this helps : )
This looks great, but I need to keep all data for each "Name" and compare all the values within those pricing, value, costs etc..
Hi @nataliad18
Can you provide the expected output it will help us get a better understanding of the usecase.
Yes - so the input is actually thousands of rows and it is not as "clean" as the one i posted. My output expectation would be similar, but it can also be several outputs (as many as there are same "groups" of values, i.e it could be
Pricing Cost Volume Value Name Change
1 0 0 0 ABC -0.2
1 0 0 0 DBC -0.1
1 0 0 0 XYZ +0.7
Pricing Cost Volume Value Name Change
1 1 0 0 DBC -0.7
1 1 0 0 ABC -0.4
1 1 0 0 XYZ +0.9
Pricing Cost Volume Value Name Change
1 0 3 0 DBC -0.6
1 0 3 0 ABC -0.1
1 0 3 0 XYZ +0.5
The eventual goal is to also identify the "outliers", i.e if the change is smaller or bigger than 2% of the average change of that "group".
Perfect - thanks!
Will accept it as a solution in a minute, but before a quick question, is there a way to then just work with data in one of the tables? (i.e will just take the first table and want to identify the changes below or above 2% average of all changes)
Hi @nataliad18
You can use the Tile tool it will number the groups for you. You can use a filter and select each group.
Workflow:
Hope this helps : )
Thanks a lot! Appreciated!
Happy to help : ) @nataliad18
Cheers and have a nice day!