Regular expression and count functions

[AbhijeetChib]

Good Day Everyone 

I have dataset where I need to divide the input based on the numbers and alphabets and then count the occurrence of the highest number of words and create an output for them as well. 

For example - 

The record has a TRUE value if it consists of both alphabets and numbers. FALSE if it just has alphabets. 

1 1123 PAMELA WRIGHT 2316 E 5th Ave,Denver,CO 80206-4205 - True 
2 MELISSA RUFF 2753 S Milwaukee St,Denver,CO 80210-6426 - True 
3 PAMELA WRIGHT  E  Ave,Denver,CO - False
4  PAMELA WRIGHT  E  Ave,Denver,CO - False
5 DANELL VALDEZ 2925 W College Ave,Denver,CO 80219-6059 - True 
6 JESSICA 1234RINEHART 4BA220 W 35th Ave,Denver,CO 80212-1902 - True 
7  PAMELA WRIGHT  E  Ave,Denver,CO - False 
8  PAMELA WRIGHT  E  Ave,Denver,CO - False
9 DENISE 1234PENTICO 4125C S Evanston Ave Cir,Aurora,CO 80014 - True 

Further more - in all these 9 records I needed to count the words and out the records with the highest number of words. 

In the above data set "Ave" is repeated 9 times so all records with "Ave" need to be in one output. 

I would appreciate any help in this 

Regards

Abhijeet 

[Qiu]

@AbhijeetChib 
It seems that Alteryx is not supporting \p{P} as punctuations.

So we maybe can do something like this.

[AbhijeetChib]

Edited the expected output. 

1. True if there are both numbers and alphabets 

2. False of there are only alphabets. 

[binuacs]

@AbhijeetChib For the second part of your requirement you can use the below workflow and make the changes

[AbhijeetChib]

Thanks, but i edited the output for the first part. 

TRUE - If the record consists of numbers and alphabets/words

FLASE - if the Record contains only alphabets/words

There is no specific pattern to the , its just random text that i need to categorize and filter. 

[binuacs · Accepted solution]

@AbhijeetChib use the below regex formula for your edited input