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SUBMIT YOUR IDEAI really don't think this is the best solution ever and I don't have access to drivetime data, but here's my solution anyway. Thanks!
Didn't have the drive times and thought of this one as a back to shcool trying to get the perpendicular bisectors of the segments of the triangle...that would find the equidistant center of the three points and any area would be a circle with that point as its center...
Since I don't have drive-time data I used an average speed --> miles radius. Other than that, mine is the same method as everyone else's.
Two different ways to get to the same result in my solution.
Dan
Like some of the others I don't have drivetime data, so I went with using a set distance to get an approximation.
Did not have access to drive times so I've checked distances beetween offices and miles radiuses - and arbitrary come up with 11.5 miles (although initially I've used 15 km)
anyway thank you for challenge - good ocassion to use spatial tools.
Did not have access to drive times so I've checked distances beetween offices and miles radiuses - and arbitrary come up with 11.5 miles (although initially I've used 15 km)
anyway thank you for challenge - good ocassion to use spatial tools.