Extraction of substrings and sorting them accordingly in appropriate columns

Question

Hello,

I have a long string of text i.e. 1 row and 1 column. I want to parse the entire string, extract substrings based on delimiters and place them in appropriate columns. Below is an example of my string:

"Backfire – To produce an unexpected and unwanted result. The company’s new efficiency measures backfired when workers protested and staged a walkout, thus stopping production completely. Balance – The remaining part or leftover amount. The publishing division accounted for 25% of the profits, and the film division for the balance."

This is how I want it to look like:

WordMeaningExampleBackfireTo produce an unexpected and unwanted result.The company’s new efficiency measures backfired when workers protested and staged a walkout, thus stopping production completelyBalanceThe remaining part or leftover amount.The publishing division accounted for 25% of the profits, and the film division for the balance.

I tried using the "Text to Columns" Node and  '"Regex" Node, however, nothing seems to work. I don't know what I am doing wrong because my Regex is giving the correct output when I try it on Regex101.com.

Any help would be highly appreciated.

-Thanks

AncientPandaman · Answer

here the workflow. you can compare it.

RegEx.yxmd

SumitVerma · Answer

Hi  Pang_Hee_Choy,

Thanks for the response. I tried your method and it seemed to work, however, it's running only for one iteration. I was not able to get the second row in the first step. Don't know what I am doing wrong.

-Thanks

AncientPandaman · Answer

split by rows first. then split to column.

Provided only two dots in every pair.

first regex: (?:\s|^)(.*?–.*?\..*?\.)

(?:\s|^) = (?:) mean do not take. \s|^ mean it start with space or it is first character. mainly to remove the space for second line onward.

(.*?–.*?\..*?\.) = mean get rows by pattern "word - anyword. anyword."

.*? = not greedy. take as least text as possible

\. = dot (add \ to tell we required the symbol)

second regex: (.*?) – (.*?\.) (.*?\.)