Advent of Code is back! Unwrap daily challenges to sharpen your Alteryx skills and earn badges along the way! Learn more now.

Weekly Challenges

Solve the challenge, share your solution and summit the ranks of our Community!

Also available in | Français | Português | Español | 日本語
IDEAS WANTED

Want to get involved? We're always looking for ideas and content for Weekly Challenges.

SUBMIT YOUR IDEA

Challenge #257: Palindromes

Blake
12 - Quasar

A man a plan a canal panama

 

Spoiler
Blake_0-1614696657756.png

 

See below for a video walkthrough.

 

Spoiler
patrick_digan
17 - Castor
17 - Castor

It's also fun to use @jdunkerley79 's alteryx abacus variable functions. You can do so much more in the formula tool.

Spoiler
patrick_digan_2-1614611473827.png

 



patrick_digan_1-1614611416638.png

 

 

Maskell_Rascal
13 - Pulsar

This was a fun one, and highlights a rarely used (at least by me) function of reversing strings. 

Spoiler
Maskell_Rascal_0-1614612923826.png

 

balajilolla
8 - Asteroid
Spoiler
Solution Attached

balajilolla_0-1614613739835.png

 

Toons
12 - Quasar

My solution :

 

Spoiler
Toons_0-1614616166556.png

 

RolandSchubert
16 - Nebula
16 - Nebula
Spoiler
257.jpg
DeanWest
9 - Comet

racecar 🏎

 

Spoiler
challenge_257_solution_DeanWest-snippet.png

 

 

jamielaird
14 - Magnetar

That was good fun. Here's my solution:

 

Spoiler
jamielaird_0-1614621017308.png

 

jamielaird_1-1614621024329.png

 

phottovy
13 - Pulsar
13 - Pulsar

No macro needed:

Spoiler
257.PNG
MPard
6 - Meteoroid
Spoiler
MPard_1-1614624038819.png

I was able to parse the palindromes with a simple formula, after that filtering to get the data was a breeze!

The formula I used to detect palindromes is:
IF ((ReverseString(Right([Words], (length([Words]) - Mod(length([Words]), 2)/2)))) = (Left([Words], (length([Words]) - Mod(length([Words]), 2)/2)))) THEN 1 ELSE 0 ENDIF

This formula takes the last half of the word (excluding one character for odd length words), flips it, and compares it to the first half of the word (excluding one character for odd length words). Awesome to see Modulo is available in the formula operation, super useful for dynamic formulas like this!