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Subtracting hours from a date time and converting to date time.

IMTran
6 - Meteoroid

Hello,

 

I'm having trouble with my date time subtracting. I first imported by data and the DATETIME_D it is in the initial format of 10/16/2022 23:00  (I believe this would be M/d/yyyy HH:mm), but there are no leading zeroes in everything.

 

IMTran_0-1674762230437.png

 

To subtract 1 hour, I used this formula: datetimeadd([DATETIME_D],-1,"hours"), and I get errors like this :  Formula (28) DATETIMEADD: "10/17/2022 8:00" is not a valid DateTime

 

Am I missing something?

 

2 REPLIES 2
Felipe_Ribeir0
16 - Nebula

Hi @IMTran 

 

When you used the DateTime tool, you correctly transformed the DATETIME_D string to datetime, and the date is now inside of the Start column. So you need to apply the datetimeadd formula using the Start column as reference:

 

Felipe_Ribeir0_1-1674762959258.png

 

Felipe_Ribeir0_0-1674762815818.png

 

IMTran
6 - Meteoroid

Thank you very much for the help! This was a big oversight. Thank you for taking the time to help out. Hope you have a good day. 

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