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Challenge #406: What Is Your Lucky Number for the New Year?

ed_hayter
12 - Quasar

My new lucky number is number six!

 

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AYXAcademy
Alteryx
Alteryx

Me too @Chris-Nienart ! 🤣🤣🤣

RolandSchubert
16 - Nebula
16 - Nebula
Spoiler
406.jpg
balajilolla2
9 - Comet
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Solution Attached
Screenshot 2023-12-27 084709.jpg
Dev73
8 - Asteroid

my lucky number is 7️⃣

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challange 406-3.pngchallange 406-2.pngchallange 406-1.png
nSpire
9 - Comet
Spoiler
406.png406-02.png
Kenda
16 - Nebula
16 - Nebula
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Kenda
16 - Nebula
16 - Nebula
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macro

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ARussell34
8 - Asteroid

Lucky number is 5!

 

AR_ 406 macro.pngAR_challenge 406_sol.png

WeiLi
7 - Meteor

I wanted a real challenge, so i did not use the start file and built everything based on the original post descriptions.

 

The results are as follows:

 

 

Spoiler

Task 1: Validate the process that all four-digit integer numbers with at least two distinct digits will transform into 6174 when applying the rules of Kaprekar’s constant.

Result: See Week406 Output, all numbers verified. There are 8991 qualifying numbers.

 

Task 2: Find the highest and the lowest number of iterations you need to transform any four-digit number into 6174 using this rule set.

Result: Highest is 7, lowest is 1.

 

Task 3: Determine your lucky number.

Result: 2


My solution used 1 Workflow, 1 Batch Macro, 1 Iterative Macro and 2 Standard Macros.

 

What is not obvious from the original question is that when you calculate the difference in step 3, the result need to be converted to 4 digits. For example, 1000 - 0001 = 999. More accurately, it is 0999. Thus, when you perform the next iteration, the number is 9990 - 0999 = 8991.

It is necessary for the larger number to always be a 4 digit number. If it is less than 4 digits, 0's need to be added to the end for this to work.

 

Solution image:

 

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Main Workflow
 
406a.PNG

Batch Macro

 
406b.PNG

Iterative Macro

406c.PNG

 In addition to these, I built 2 standard macros, as I did not rely on RegEx, so parsing macros were created instead.