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SUBMIT YOUR IDEASolved! That was fun!
Not quite as pretty as the official solution but I had an easier time doing some "dumb" parsing just to get rid of most of the excess data and then some proper RegEx parsing. I also fell for the trick where things like "Marrying" and "Separator" were included which will cause issues if you're looking for "Mar" or "Sep" but I handled it later
ok done.
simply copy-paste regex formula to extract the date, then voila... wow
Slightly different method than the posted solution, got to love combining regex and Alteryx, so many methods to get to the right answer
regex code on mine was this: (\d{2}-\w+-\d{2,4})|(\d-\w+-\d{2,4})|(\w{3} \d+ \d{2,4})|(\w{3} \d+, \d{2,4}) and since I landed with 4 columns from the groups I used the arrange tool to put them into one column and a filter to remove the nulls
Dear Trainer
To difficult to understand below formula.
if anyone have literature or module easy to understand below formula to find the phrase.
.*(\d\d-[[:alpha:]][[:alpha:]][[:alpha:]]-\d+).* |
.*(\u\l\l\s\d+,*\s\d\d+).* |
.*(\d+-\u\l\l+-\d\d+).* |
.*(\d-[[:alpha:]][[:alpha:]][[:alpha:]]-\d+).*
Please find my solution for Challege#4
Thank You.
Hamdan Khawashi
Hi, I have built 1 long expression from scratch to have all outputs in the same column. I am glad to break it down to pieces and explain briefly . Here is the output
(\d{2}-\<\w+\>-\d+|\<\u\w+\>\s\d+,*\s\d+|\d+-\<\u+\>-\d+)