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Challenge #159: April ENcyptanalytics

ed_hayter
12 - Quasar

Loved this challenge - not too hard but still very satisfying to build.

 

 

Spoiler
I opted for the logic of an iterative macro that looped the same original statement again and again if random was less than 0.15 then use the true character otherwise replace with a random character. Looped it 100 times and then feed into the decryption macro that recognizes the original character as the most regularly occurring and therefore decrypts the message.

image.png
image.png

 

 

gawa
15 - Aurora
15 - Aurora

DOne

geoff_zath
Alteryx
Alteryx
Spoiler
challenge_159_workflow.png

olga_strubbe
11 - Bolide

Thank you, @TerryT .  This was fun! 

Please see my solution attached.

2024-02-12_13-38-43.png

CeliaC_Silje
8 - Asteroid

RandFromInt() and RandToInt() functions helped the encoding process!