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Challenge #159: April ENcyptanalytics

ed_hayter
クエーサー

Loved this challenge - not too hard but still very satisfying to build.

 

 

スポイラ
I opted for the logic of an iterative macro that looped the same original statement again and again if random was less than 0.15 then use the true character otherwise replace with a random character. Looped it 100 times and then feed into the decryption macro that recognizes the original character as the most regularly occurring and therefore decrypts the message.

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gawa
16 - Nebula
16 - Nebula

DOne

geoff_zath
Alteryx
Alteryx
スポイラ
challenge_159_workflow.png

olga_strubbe
ボリード

Thank you, @TerryT .  This was fun! 

Please see my solution attached.

2024-02-12_13-38-43.png

CeliaC_Silje
アステロイド

RandFromInt() and RandToInt() functions helped the encoding process!

karlhansen
コメット
スポイラ
solution_159.png

My solution runs properly through my completed #155 but not through their decoder.