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Alteryx Designer Desktop Discussions

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SOLVED

Populating empty columns

peterg97
7 - Meteor

Hi All, 

 

I am trying to populate a column using an IF function, but not sure how to do it. Basically, I want use an IF function to check if a row in a column is null, and if it is, I want to replace it with the first 4 characters of a different row. I've attached an example to help visualise (For the rows that are Null, I want the first 4 letters ie 2017, 2018 and 2011 to populate the year column):

peterg97_0-1610014822207.png

 

Any help would be appreciated.

 

Hope everyone had a good New Years!

 

Cheers!

5 REPLIES 5
Qiu
21 - Polaris
21 - Polaris

@peterg97 
Something like this?

0107- peterg97.PNG

Emil_Kos
17 - Castor
17 - Castor

Hi @peterg97,

 

This is the formula that you need to use:

 

IIF(IsNull([Year]), ToNumber(Left([Order], 4)) , [Year])

 

My output:

Emil_Kos_0-1610015458664.png

 

 

peterg97
7 - Meteor

Hi @Qiu 

 

Thanks, this works perfectly! Appreciate the help. 

 

Kind Regards, 

Peter. 

peterg97
7 - Meteor

Hi @emil 

 

Thanks! Appreciate the help!

 

Kind Regards, 

Peter. 

Qiu
21 - Polaris
21 - Polaris

@peterg97 

Thank you for the accept mark also

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