How to dynamically name files without creating new column

[Gkiely]

I have a workflow which creates a dataframe. I'd like to share this file as an .xlsx file by email with the file name updating dynamically with today's date. I've done this by using the formula function to create a file name column with today's date, and subsequently change my file path in the output function.

Is there a way to do this without adding a new column of file paths to my dataframe? either an alternative way to dynamically name files or simply a way to remove the additional file name column created prior to exporting it?

[Bobbyt23 · Accepted solution]

If you are writing the output in the tool you can take the filename from a field and choose whether to include that in the output or not. Is that what you mean?

[Gkiely]

Thank you, that is exactly what I was looking for.