I have a workflow which creates a dataframe. I'd like to share this file as an .xlsx file by email with the file name updating dynamically with today's date. I've done this by using the formula function to create a file name column with today's date, and subsequently change my file path in the output function.
Is there a way to do this without adding a new column of file paths to my dataframe? either an alternative way to dynamically name files or simply a way to remove the additional file name column created prior to exporting it?
Solved! Go to Solution.
If you are writing the output in the tool you can take the filename from a field and choose whether to include that in the output or not. Is that what you mean?
Thank you, that is exactly what I was looking for.