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[Elena_B1]

Hello, Kindly help to correct the formula. IF Contains[ACCOUNT], [0-9] THEN "" ELSE [ACCOUNT] ENDIF

To check if a field named [ACCOUNT] that is a string contains any digits and return an empty string if it does, and the original field otherwise.

Thank you.

[binuacs · Accepted solution]

@Elena_B1 One way of doing this with the Regex_CountMatch function

IIF(REGEX_CountMatches([Account], '\d') > 0, '', [account])

[alexnajm · Accepted solution]

IF Regex_Match([ACCOUNT],".*\d.*")=-1 THEN "" ELSE [ACCOUNT] ENDIF

Edit: just beat me @binuacs, great solution too!

[SPetrie · Accepted solution]

The contains formula needs parentheses to be in proper syntax.

IF Contains([ACCOUNT], [0-9]) THEN "" ELSE [ACCOUNT] ENDIF

The problem you will still run into is that it will be looking for a column named [0-9] and expecting a string there, so it wont really do what you want it to do.

You may have better results using a regex match formula

if REGEX_Match([Account],".*[0-9].*") then "" else [Account] endif