Bring your best ideas to the AI Use Case Contest! Enter to win 40 hours of expert engineering support and bring your vision to life using the powerful combination of Alteryx + AI. Learn more now, or go straight to the submission form.
Start Free Trial

Alteryx Designer Desktop Discussions

Find answers, ask questions, and share expertise about Alteryx Designer Desktop and Intelligence Suite.

To get end date from start date

Polite123
8 - Asteroid

Hello team,

 

Need some suggestion regarding below issue.Please help

 

Input:

Start Date
1/1/2021
2/1/2021
3/1/2021
4/1/2021
5/1/2021
6/1/2021
7/1/2021
8/1/2021
9/1/2021
10/1/2021
11/1/2021
12/1/2021

 

Output:

 

Start DateEnd Date
1/1/20211/31/2021
2/1/20212/28/2021
3/1/20213/31/2021
4/1/20214/30/2021
5/1/20215/31/2021
6/1/20216/30/2021
7/1/20217/31/2021
8/1/20218/31/2021
9/1/20219/30/2021
10/1/202110/31/2021
11/1/202111/30/2021
12/1/202112/31/2021

 

 

Thnaks in advance.

 

 

4 REPLIES 4
PhilipMannering
16 - Nebula
16 - Nebula

Hi @Polite123 ,

 

You can use this Formula,

DateTimeFormat(DateTimeAdd(DateTimeAdd(datetimeparse([Start Date], '%m/%d/%Y'), 1, 'month'), -1, 'day'),
'%m/%d/%Y')

 

AngelosPachis
16 - Nebula

Hi @Polite123,

 

You can use the datetimetrim function after you convert your input to a format that Alteryx can understand as a date.

 

AngelosPachis_0-1614273458931.png

 

Regards,

 

Angelos

messi007
15 - Aurora
15 - Aurora

@Polite123,

 

Please see below:

 

messi007_0-1614273809970.png

Attached the workflow,

 

Regards,

Polite123
8 - Asteroid

Amazing!! Thank you both you for your prompt response.

Much appreciated.Thanks again.

Labels
Top Solution Authors