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Question about using regex with if functions

wht822
7 - Meteor

I couldn't find the answer to this question anywhere else on this forum, so I apologize if this has been asked before.

 

I'm trying to enter a regex function into an if field so I can identify certain data sets. In this case, I'm trying to apply an if function to records that contain a date in "mm/dd/yyyy" format at the beginning of the record and end with either a percentage sign (%) or a decimal followed by two numbers.

 

An example of a record might look something like this: "03/23/20 12.000 210.6380 2,527.65 379.9100 4,558.92 2,031.27 7.68 0.16%"

 

Or this: "03/23/20 14.000 306.0690 4,284.97 435.3100 6,094.34 1,809.37"

 

If a record contains something within either format listed above, then I want a new field to display "Format 3."

 

I'd really appreciate if someone could help point me in the right direction. Thanks!

2 REPLIES 2
Qiu
21 - Polaris
21 - Polaris

@wht822 

Something like this?

Appreciate if you would mark it as acceptable if you think it works for you.

1029-wht822.PNG

vizAlter
12 - Quasar

Hi @wht822 — Try this solution:

 

REGEX_Replace([Field1], "^(\d{2}/\d{2}/\d{2}\s.*)(?=\.\d{2}%|\.\d{2})", "")

then

  IF   REGEX_Match([Result], "^\.\d{2}\%$")  OR  REGEX_Match([Result], "^\.\d{2}$") THEN 
    "Format 3." 
  ELSE 
    Null() 
  ENDIF

vizAlter_0-1603942116004.png

 

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