Hey there. I want to check if the minimum (the fastest who finished) is also the fastest in finishing 1st and 2nd rounds.
Basically, I want to check if the three minimums belong to the same person, while using a dynamic method if future data was captured.
I converted the time to seconds and minutes to compare
Hi @Dennis229
I have gone through the workflow, It seems you have already done the entire part.
Only missing item was to identify the minimum of 3 belongs to the same person.
The input of the person name is missing, if you have the name of the players, then you can use the summarize tool by adding Group by by Person name.
This will help to give you the count by person name. If =3 or >3 then its by the same person, then that person has maximum minimum values.
Many thanks
Shanker V
Hi @Dennis229
Now I read you question/statement in another way.
Where you have 2 containers, and 1st container contains 1st Lap time and 2nd Lap time
Container 2 contains Finish time for the entire lap.
I am modifying the workflow as below to check all the 3 minimum of 1st Lap and 2nd Lap and Entire Lap is achieved by the same person or not.
Many thanks
Shanker V
Hi @Dennis229
Modified Workflow:
Record ID tool:
This makes use of distinct name for each record as I do not have specific names
Summarize tool:
To get the minimum of 3 laps
Many thanks
Shanker V
Hi @Dennis229
Now as I have only the minimum value of all 3, I dont know the name of the person who completed the first lap.
Using Join tool to get the result.
So Person 8 was the one who completed the First Lap very soon.
Repeating to check for second Lap and Full lap.
Hi @Dennis229
Person 3 was earliest to finish the 2nd Lap.
Person 8 was the fastest to complete the Full Lap.
Hi @Dennis229
Union tool helps to link all the 3 outputs to compare.
Using Multi Row formula to display the output.
if ([RecordID]=[Row+1:RecordID]=[Row+2:RecordID])
then "All the 3 minimum are achieved by same person"
else "3 minimum are achieved by different person"
endif
Sample tool
Select tool
Many thanks
Shanker V
@shankerV
If there are many more than two rounds this solution would be hard to scale. Could you please find another way of approaching the problem
.