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How to convert datetimetoday() to dd-Mon string format?

kalindideshmukh
7 - Meteor

Hello Alteryx designers,

 

My aim is to filter my rows that match with datetimetoday() function in dd-Mon format.

My dataset has variable 'Date' in the dd-Mon format (example: 01-Dec). Alteryx identifies it as a string. I tried two ways:

 

1. Converted using the Date Conversion tool, but the output date looks like 01-Dec-1400; the year 1400 gets attached to every date. If I could remove the year or add 2019 to every date, that would work.

 

2. Filter function tool that compares Date with datetimeparse for datetimetoday in dd-Mon format, but it shows 0 records.

 

It would be great if either of the ways was fixed. 

 

Thanks

 

Kalindi

2 REPLIES 2
MichalM
Alteryx Alumni (Retired)

@kalindideshmukh 

 

You can use the formula tool to parse the DateTimeToday into the format you need

DateTimeFormat(DateTimeToday(), "%d-%h")

 

dttoday.png

kalindideshmukh
7 - Meteor

@MichalM

Great, it worked! Thanks.

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