Hi Everyone
I am looking for a formula to extract date from a file name 'communication.clientreporting.statements.bds.sr.20190118_095020.xml'
For all the files the date will always be at this location.
Best
Pooja
解決済! 解決策の投稿を見る。
You can use a formula like this
REGEX_Replace([Filename], ".*(2\d{7}).*", "$1")
Workflow:
Hope this helps : )