Row contains all digits then True

[wonka1234]

Hi all,

Does anyone know how to update a column if a row contains all digits then True?

Not sure how to do the all digits part in a formula.

Thanks.

[csmith11]

REGEX_Match([Test Column], "\d*")

Please see attached a workflow with this solution implemented.

If this helps, please consider marking as the solution so other users can identify solutions faster.

Please let me know if you have any questions.

Cheers!

[OllieClarke · Accepted solution]

Hey @wonka1234 I would tweak @csmith11's regex so that it's REGEX_MATCH([Test Column],'\d+'). This will ensure that the column contains only digits, and that there is at least 1 digit in there - if we used '\d*' then nulls and/or empties would come back true

[csmith11]

 @wonka1234  I fully agree with @OllieClarke. This is a great point!

[wonka1234]

hi @csmith11  and @OllieClarke , having trouble implementing it, getting the result as 0. Could this be related to data type?

[OllieClarke]

Hey @wonka1234 sorry, we interpreted your request as checking that the row is made of only digits. If you want to check that it contains at least 1 digit then use the following formula:

Regex_CountMatches([Field],'\d')>0

Hope that helps,

Ollie