Hi all,
I have one input file and I am simply looking to do a replace all where in one column it says FALSE, I'd like for it to be blank or " ", and if TRUE then it says "X". I can easily do it in excel and assume I am just overlooking the method to do so in Alteryx as I must do this multiple times a day.
Thank you for any guidance!
Solved! Go to Solution.
Hi @comckinley
You can use a Formula tool as follows:
IF [Field] = "FALSE" THEN "" ELSE "X" ENDIF
This assumes that all the rows have a value of FALSE or TRUE and that the field has a string type.
If you want to be more explicit and return a null if the field didn't contain FALSE or TRUE use the following:
IF [Field] = "FALSE" THEN "" ELSEIF [Field] = "TRUE" THEN "X" ELSE Null() ENDIF
Have a play around with the Formula tool and I'm sure you will get the hang of it.
@comckinley Here are a few different options for your formula tool assuming your field is a string with either FALSE or TRUE
IF [Field] ="FALSE" Then "" Else "X" ENDIF
Replace(Replace([Field],"FALSE",""),"TRUE","X"))
Thank you so much!!
Thank you so much!
You're welcome!
By the way, single or double quotation marks are both acceptable in the Formula tool. You don't even need to be consistent, other than making sure that you open and close each particular instance with the same style.
I'm pleased to see that @patrick_digan is in team double-quotation marks, which is obviously the best way.
@jamielaird I'm very much on #TeamDoubleQuotes. It's admittedly less efficient than single quotes since I have to hit the shift key, but it's a habit that I can't break.
@patrick_digan it's like our own version of tabs-versus-spaces