Need some help with a RegEx pattern (example below)

[AkisM]

My data looks like this:

Column1

, m. 05/31/2022
, m. 01/12/2021
, m. 09/12/2022

I need a regex command that splits this into 2 capture groups:  1. ", m. "

                                                                                                     2. "09/12/2022"

I tried this expression ([,\s m.])(\d{2}\/\d{2}\/\d{4}) but it gives me only the date from the 2nd capture group. Nothing captured from the first group. Any ideas?

[AkisM · Accepted solution]

Nevermind, got it. It should be (\,\s\w\.\s)(\d{2}\/\d{2}\/\d{4})

[MichalM]

In this case you could also use the below

(.+)(\d{2}\/\d{2}\/\d{4})