Hi,
I want to assign Record IDs to my record like starting from AB1 to AB1000032.. How do I do it in alphanumeric style
Thank you
Solved! Go to Solution.
"AB"+[RecordID]
Cheers,
Mark
Hi Mark,
I found your response very helpful.
Do you know of any other ways to create an alphanumeric string? I was able to follow the first two steps to create the numeric half of the RecordID. However, I'm unsure how to assign a unique alpha ID.
Ideally I'd like the RecordID to be "AB011111", "AC011112", "AD011113" etc.
Do you know if something like this is possible?
Thanks for any help!
Elizabeth
@MarqueeCrew wrote:
4. Have a cup of coffee...
@MarqueeCrew Does it have any impact on the process if you do 4 first?
Using an ascii table, you can identify decimal values as 65-90 as A-Z. We know that there are 26 letters in the alphabet. If you divide a number, say 345 by 26 you get:
13 with a remainder of 7. I know that the 13th letter of the alphabet is "M" and that the 7th letter is "G". If I were to add 12 to 65 (the 0 offset), I get 77 and looking that up in the table, I find "M" and I suspect that I'll find "G" by adding 6 to 65 (or by adding 7 to 64).
Back to my cup of coffee @LordNeilLord ....
So I can create values with much larger numbers by using this base26 logic if needed. It just takes a little imagination.
Cheers,
Mark
Apologies - brand new to using Alteryx.
How would I incorporate the ascii decimal values into the RecordID? I'm assuming a formula tool... just not sure which actual formula to use.
Please do open a new question to the community and provide more details about your ID schema (what you want it to do).
Cheers,
Mark