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SUBMIT YOUR IDEAChallenge complete - similar solution to others 🙂
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Solution:
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Awesome challenge; I took something of a 'brute force' approach to it. 🙂
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Solution attached. Similar to others I used a Cartesian join and the FindString function. My stumbling block was getting the concatenated groups, which turned out to be quite simple once I saw that action was available with the Summarize tool.
Ken
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I can't stop laughing after knowing solution is this simple. I used so many filters and formulas(to calculate intersections and then excluding it) in the end to get to the answer,
Here's my solution.
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Solution attached
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Here's my solution for this one.
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