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SUBMIT YOUR IDEAhmm... getting a different answer by using trig calcs... very close, so i'm assuming it isn't taking curvature into account or something silly like that???
Think I used a bit of spatial and trig. I created all the points then just found the distance/angle with trig. Think I had to convert from radians to degrees so maybe that's why I'm off .05 degrees.
Done with a mixture of spatial and trig first (could be easily converted to formulas) then simplified to pure spatial. Hadn't realised that radians not degrees were the default for trig formulas.
My solution.
about Bonus question:
I calculate them as a points on the surface of the sphere(r=6378.137km)