A solution to last week's challenge can be found here.
This challenge was submitted by Alteryx ACE Esther Bezborodko @estherb47 . Thank you, Esther!
Use Designer Desktop or Designer Cloud, Trifacta Classic to solve this week's challenge.
This challenge is a variation on the New York Times Spelling Bee puzzle. For this challenge, we will use the same list of words we used in Challenge #356.
Although Merriam-Webster’s Dictionary defines a pangram as “a short sentence containing all 26 letters of the English alphabet,” for the purposes of the New York Times Spelling Bee, their Glossary defines a pangram as a word that uses seven unique letters and is worth seven extra points. We will use this definition as a guide for our challenge.
Your goal here is to find, within the list of words, the pangram with the highest point value and the individual letters that comprise that word. For that, you need to do the following:
Find all the words within the list with seven unique letters. It does not matter if the word uses a unique letter more than once; this letter will still be unique within the word. For example:
Alteryx has seven unique letters.
Statistically also has seven unique letters.
Once you find the words with seven unique letters, determine their point value. Each letter is worth one point. For a pangram, the point value is calculated by adding 7 to the value for the length of the word. For example, in ALTERYX, the total value is 14 points (7 [the word length] + 7 [pangram extra points]).
The result should look like this: