First Challenge--I came up with a different solution than posted, but this one seems to work. Are their pros/cons to solving this problem in different ways? I used 3 text to columns and datetime to come up with my solution. It was more tools than the posted solution. I assume the benefit is efficiency?
Done in a slightly different order than the posted solution, and with two solutions that yield the same result. Both the StripQuotes and ReplaceChar functions work equally well to remove the quotations in this instance.
Learnings/assumptions I've gathered from this challenge:
1) Using the ReplaceChar function...
a) for the apostrophes, the character needed to be encased in quotations - I assume this is the case for all characters other than quotations?
b) for the quotations, the character needed to be encased in apostrophes - is this unique to replacing quotations?
2) The DateTimeParse function requires that the format of the incoming string data be defined as part of the function. In the case of this challenge "%d-%b-%y" and outputs in the the standard ISO format yyyy-mm-dd
a) %d = Day of the month ("16" and "25")
b) %b = Abbreviated month name ("JUN" and "DEC")
c) %y = Last two digits of the year ("01" and "10")
Please respond if these assumptions are incorrect or if there's anything to add
Responding to my last post to clarify some of my own questions... either apostrophes or quotations can be used as part of the ReplaceChar function, however it is still correct that apostrophes need to encase a quotation mark to remove it, while quotations would need to encase an apostrophe. Both can be used for other characters