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## Challenge #168: Dice Game - Born to Solve

Meteoroid

Meteor

It's not an elegant solution, but it gets the job done...

Meteoroid
It’s my first one. I’ll get better 😊
Meteoroid

Fun challenge! Looks I came up with the same workflow as @EstherB47, but without a 1000 eyes and ears on me! :) Good one Esther!

Spoiler

Meteor
Spoiler
I leveraged one formula to take care of calculating all the P&Cs and summarised to identify max probability score.
Aurora

Congrats to @EstherB47 , and excellent challenge @patrick_digan

I have to echo @NicoleJohnson's sentiment here.  Sorry I missed it, but there was just so much to see at Inspire!

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Dan

Quasar

@danilang I am so glad to have met you in person at Inspire this year!!! Putting faces to community handles was a wonderful highlight of the week.

Aurora

I totally agree @EstherB47

Learning new things is fun, but meeting new people is more enriching.

Dan

Highlighted
Asteroid

Hello @T_Willins  I understand that when the 3 dices are thrown it is an independent event, but listing all the possible combinations would mean that there would be 36 combinations where two dices have the same value; for example: 6-6-1 or 1-1-6. Since those combinations belong to the universe of possible combinations, it means that when taking the highest, mean, and minimum of those combinations, a combination would be repeated.

I may be wrong, but I think 36 events need to be excluded and filtered out.

Thanks for taking the time to reply.

Meteor

Here is my solution

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