Hi Maveryx,
Thanks for submitting your solutions for Cloud Quest #2! In the video solution we posted, Alteryx Chief Evangelist Josh Burkhow will guide you through the workflow.
Now, for this week’s quest, let's delve into the task of ranking records when there can be multiple records with the same rank.
Using the provided dataset that contains two columns [Name] and [Count], your goal is to identify the top five rankings based on the count. However, as there might be several rows with identical counts (similar to a round of golf), multiple individuals can occupy the same position (Rank) if they share the same score.
Your final result should look like the following image:
Hint: Identify the top five positions (ranks 1 through 5) based on the Count column before proceeding with your analysis.
A combination of Join, Summarize, Sample, Row ID, and Sort tools should solve your problem, not necessarily in this sequence.
If you find yourself struggling with any of the tasks, feel free to explore these interactive lessons in Maveryx Academy for guidance:
Here’s to a successful quest!
We want to hear from you!
As we introduce our Cloud Quests for the first time, we value your input. Share your thoughts on the clarity of instructions, the provided dataset, the expected output, and any suggestions to enhance your experience.
Thank you!
Had to solve this differently than I might have on Desktop, this is exactly the reason why doing cloud challenges is so good!
Solved during the Australian Cloud Weekly Challenge Hour by myself, @leofrancia , Jimmy and Charlie!
This one was nice
Here is the workflow I created for a solution.
Interesting that the tile tool doesn't rank like it does in Designer. For example, I have my rows sorted in a descending order, based on a column. I select "unique value" on that column, using the tile tool. It then returns the ranks but in reverse order i.e. largest rank assigned to the first row it sees.
All the best,
BS
I might have done this slightly differently in Designer, but a simple one nonetheless.