This site uses different types of cookies, including analytics and functional cookies (its own and from other sites). To change your cookie settings or find out more, click here. If you continue browsing our website, you accept these cookies.
I converted the input to ISO datetime formats then calculated both hours and days. For hours, I used a mod() function to find the hours left over when you divide the result by 24 (e.g. Mod(25,24) = 1). I then concatenated the strings with conditional logic so that 1 hour reads without 1 hours.
Alteryx ACE & Top Community Contributor
Chaos reigns within. Repent, reflect and reboot. Order shall return.