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SOLVED

IF THEN Statement

AgiGovind
6 - Meteoroid

Hello - 

 

I'm trying to write the following formula in Alteryx; wondering if anyone could help:

 

if [difference] <=1 and [difference] >=-1 then "round off"

else " " endif

 

So any value between -1 to +1 should be commented as 'Round off' except 'zero' it should be blank.  

 

Output:

DifferenceComment
-0.36Round off
-0.25Round off
0 
0 
0.45Round off
3 REPLIES 3
A1exW
6 - Meteoroid

IF [Difference] = 0 then ""
elseif [Difference]<=1 and [Difference] >=-1 THEN "round off"
ELSE "" ENDIF

nagakavyasri
12 - Quasar

if [difference] <=1 and [difference] >=-1 and [difference]!=0 then "round off" else " " endif

apathetichell
20 - Arcturus

tbh --- you're pretty close here --- probably good practice for you to just add another formula tool and force convert 0 from round off to '' 

 

I'd use --> if abs([difference])>0 and abs([difference])<=1 then "round off" else "" endif

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