How to get the correct format of (09/17/2022) = (09-17-2022) ?

[Pranati_Pradhan_6372]

Unable to find (09/17/2022) = (09-17-2022)

[Pranati_Pradhan_6372 · Accepted solution]

unable to find (09/17/2022) = (2022-09-17)

[binuacs]

@Pranati_Pradhan_6372 use the DateTimeFormat and DateTimeParse functions to achive this

[binuacs · Accepted solution]

@Pranati_Pradhan_6372 for the ISO format only use the DateTimeParse() function