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How do i extract all data to the right after a specific character

Jdelagu11
5 - Atom

I'm trying to extract all the data from a field after the very last underscore "_" in the data (see below screenshot).

 

So the data highlighted in RED would be the extract. I tried using formulas but nothing seems to work. Can this be done in a formula?

... or does it need to be done in REGEX? If it needs to be done in regex, can someone help me with what the code would like?

Still a beginner with REGEX unfortunately.

 

2024_08_07_August RNR Green FB_A24FN170DAADAAD
2024_08_05_August RNR TS AM FB_A24FN206DAADAAD
2024_08_05_August RNR TS AM_B24FN206DAPDAARR
2024_08_05_August RNR TS AM_A24FN207DANOA
2024_08_05_August RNR TS AM_G24FN206

 

Thanks for any help!  Javier

 

4 REPLIES 4
binu_acs
21 - Polaris

@Jdelagu11 one way of doing this

image.png

Jdelagu11
5 - Atom

That worked! Thanks so much for the quick resolution! I'm going to have to start studying what all those characters mean! :)

Jdelagu11
5 - Atom

I used the below code to pull out all the data in RED in a formula tool:

 

REGEX_Replace([FieldName],'.*_(.*)', '$1')

 

2024_08_07_August RNR Green FB_A24FN170DAADAAD
2024_08_05_August RNR TS AM FB_A24FN206DAADAAD
2024_08_05_August RNR TS AM_B24FN206DAPDAARR
2024_08_05_August RNR TS AM_A24FN207DANOA
2024_08_05_August RNR TS AM_G24FN206

 

This worked great but now i need to pull out all the data in red after the character "\". How would i alter regex below to do this?

 

I tried this - but that didn't work:

REGEX_Replace([FieldName],'.*\(.*)', '$1')

 

2024_08_07_August RNR Green FB\A24FN170DAADAAD
2024_08_05_August RNR TS AM FB\A24FN206DAADAAD
2024_08_05_August RNR TS AM\B24FN206DAPDAARR
2024_08_05_August RNR TS AM\A24FN207DANOA
2024_08_05_August RNR TS AM\G24FN206

 

Any thoughts would be greatly appreciated. Thanks.

Jdelagu11
5 - Atom

I'm starting to think the forward slash \ is not allowed in Regex?

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