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Weekly Challenge #168
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Suppose you have 3 ordinary dice (6 sides with the numbers 1-6). You roll all 3 dice and compute the score like so: Multiply the largest number by the second largest number. Then add the remaining number. Given this unique method of scoring, which is the most likely score?
Output
13
12
Allow
Allow
Normal Approach
Warn
RecordID
1
Int32
6
0
RecordID - Ascending
Value - Descending
RecordID
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Int32
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Empty
[Row-1:Index]+1
[Row-1:Index]+1
Count - Descending
First
1
First 1
Function Approach
Score = Max([Dice1],[Dice2],[Dice3])*Median([Dice1],[Dice2],[Dice3])+Min([Dice1]...
Count - Descending
First
1
First 1
Horizontal
challenge_168_start_file_AK