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Weekly Challenge #168
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Suppose you have 3 ordinary dice (6 sides with the numbers 1-6). You roll all 3 dice and compute the score like so: Multiply the largest number by the second largest number. Then add the remaining number. Given this unique method of scoring, which is the most likely score?
Output
13
12
Allow
Allow
RecordID
1
Int32
6
0
Warn
RecordID - Ascending
Value - Descending
RecordID
Score
Int32
4
Empty
([Value]*[Row+1:Value])+[Row+2:Value]
([Value]*[Row+1:Value])+[Row+2:Value]
First
1
First 1
Count - Descending
First
1
First 1
UniqueValue
Unique Value
Count - Descending
First
1
First 1
Score = if [Dice1] <= [Dice2] and [Dice1] <=[Dice3]
then [Dice2]*[Dice3] + [Dic...
Count - Descending
First
1
First 1
Horizontal
168.