RegEx Parse formula for variable length times

Hello All,

I am using a RegEX tool to parse times using the following formula: (\d{2}:\d{2}:\d{2}.\d{3}) in this format: 00:00:14.522

The problem I have is when the runtime is under 10 seconds the time appears like this: 00:00:8.304 ith only a single digit for seconds (this doesn't happen for single minute or hour values).

Is there any way to put a range for the number of digits at the highlighted part of the formula?

(\d{2}:\d{2}:\d{2}.\d{3})

Appreciate any help.

Josh

Regex

Accepted answers

neilgallen

@JoshMcG You can specify a range as {2,#} where # is the upper end of your range, and flip this for a lower end.

Alternatively I believe you could write it as \d+:\d+:\d+.\d+ and it should capture any digits between the symbols.

All comments

neilgallen

@JoshMcG You can specify a range as {2,#} where # is the upper end of your range, and flip this for a lower end.

Alternatively I believe you could write it as \d+:\d+:\d+.\d+ and it should capture any digits between the symbols.

j_acon

Not an Regex Expert. There might be a better way to do it. But the below 2 work for me

(\d{2}:\d{2}:\d{1}.\d{3}) | (\d{2}:\d{2}:\d{2}.\d{3})

(\d{2}:\d{2}:(\d{1}|\d{2}).\d{3})

JoshMcG

neilgallen

This solution worked: \d+:\d+:\d+.\d+

This one did not: {2,#}

Thanks very much for your time and help, appreciate it,

Josh

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