HI Guys,
Can someone help me modify the formula below to get the date on the filename. Example
0000220454_20230710_FE_v01.xks
0000110383_20230721_FE_v01.xks
The formula is
DateTimeParse(REGEX_Replace([FileName], '[^\d{8}]', ''),'%Y%m%d')
I also welcome new ideas.
Thank,
Kamen